Let's assume that there exists one such Pythagorean triple. Then, we must have:
[math](x^2)^2 + (y^2)^2 = (z^2)^2[/math] for [math]x, y, z[/math] positive integers. Therefore, we take:
[math]\begin{align} (x^2)^2 + (y^2)^2 &= (z^2)^2 \\ x^4 + y^4 &= (z^2)^2 \tag{1} \end{align}[/math]
We have to show that this Diophantine equation do...
Không có nhận xét nào:
Đăng nhận xét