Let's solve this problem!
First, we have the expression [math](x^x)(\ln{x}+1)=0.[/math]
By the product rule, either [math]x^x [/math] or [math]\ln{x}+1 = 0. [/math]
We set [math]x^x=0.[/math] This equation is indeterminate, as there is no number [math]x[/math] that satisfies this eq...
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