Yes, that is correct.
Take any set [math]A.[/math] Then the power set of [math]A[/math] is denoted by [math]\mathcal{P}(A)[/math] and it is the set that contains all of the subsets of [math]A.[/math] Hence, [math]\mathcal{P}(A)[/math] is a set.
Now, the empty set, [math]\emptyset[/math], is a ...
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