Since the numbers in the roots are both above 1, you can set an inequality to guess then raise them to the power of 6 to test your hypothesis.
[math]\displaystyle \sqrt[3]{3} \gt \sqrt{2}[/math]
[math]\displaystyle (\sqrt[3]{3})^6 \gt (\sqrt{2})^6[/math]
[math]\displaystyle 3^\frac{6}{3} \gt 2^\frac{6}{2}[/math]
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